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question:Burt spent 2.00 on a packet of basil seeds and 8.00 on potting soil. The packet of seeds yielded x basil plants. He sells each basil plant for 5.00 at the local farmer's market. What is the net profit from his basil plants? If we know the answer to the above question is 90, what is the value of unknown variable x?

answer:Burt spent 2.00 on a packet of basil seeds and 8.00 on potting soil, so his total cost is 2.00 + 8.00 = 10.00. The packet of seeds yielded x basil plants, and he sells each basil plant for 5.00, so his total revenue is 5.00 * x. The net profit is the total revenue minus the total cost: 5.00 * x - 10.00. We are given that the net profit is 90.00, so we can write: 5.00 * x - 10.00 = 90.00. Adding 10.00 to both sides, we get: 5.00 * x = 100.00. Dividing both sides by 5.00, we get: x = 20. The value of x is 20. 20 The answer is: 20

question:f the cross product of vectors mathbf{a} and mathbf{b} is begin{pmatrix} 5 4 -7 end{pmatrix}, what is the cross product of vector mathbf{a} and the vector obtained by multiplying vector mathbf{b} by 3?

answer:The cross product of vectors mathbf{a} and mathbf{b} is given by mathbf{a} times mathbf{b} = begin{pmatrix} a_2 b_3 - a_3 b_2 a_3 b_1 - a_1 b_3 a_1 b_2 - a_2 b_1 end{pmatrix}, where mathbf{a} = begin{pmatrix} a_1 a_2 a_3 end{pmatrix} and mathbf{b} = begin{pmatrix} b_1 b_2 b_3 end{pmatrix}. So, if mathbf{a} times mathbf{b} = begin{pmatrix} 5 4 -7 end{pmatrix}, we know that a_2 b_3 - a_3 b_2 = 5, a_3 b_1 - a_1 b_3 = 4, and a_1 b_2 - a_2 b_1 = -7. If we multiply vector mathbf{b} by 3, we get mathbf{c} = begin{pmatrix} 3b_1 3b_2 3b_3 end{pmatrix}. Then, the cross product of vector mathbf{a} and vector mathbf{c} is mathbf{a} times mathbf{c} = begin{pmatrix} a_2 c_3 - a_3 c_2 a_3 c_1 - a_1 c_3 a_1 c_2 - a_2 c_1 end{pmatrix}. Using the values we have, we can simplify this expression to mathbf{a} times mathbf{c} = begin{pmatrix} a_2 (3b_3) - a_3 (3b_2) a_3 (3b_1) - a_1 (3b_3) a_1 (3b_2) - a_2 (3b_1) end{pmatrix} = begin{pmatrix} 3(a_2 b_3 - a_3 b_2) 3(a_3 b_1 - a_1 b_3) 3(a_1 b_2 - a_2 b_1) end{pmatrix} = begin{pmatrix} 3(5) 3(4) 3(-7) end{pmatrix} = begin{pmatrix} 15 12 -21 end{pmatrix}. Therefore, the cross product of vector mathbf{a} and the vector obtained by multiplying vector mathbf{b} by 3 is boxed{begin{pmatrix} 15 12 -21 end{pmatrix}}.The answer is: begin{pmatrix}1512-21end{pmatrix}

question:f Monica made a total of 30 cookies and her father ate 10, her mother ate half as much as her father, and her brother ate 2 more than her mother, how many cookies are left for Monica?

answer:Monica made a total of 30 cookies. Her father ate 10 cookies, so there are 30 - 10 = 20 cookies left. Her mother ate half as much as her father, so she ate 10 / 2 = 5 cookies. There are now 20 - 5 = 15 cookies left. Her brother ate 2 more than her mother, so he ate 5 + 2 = 7 cookies. There are now 15 - 7 = 8 cookies left for Monica. 8 The answer is: 8

question:There are 6 times as many lab coats as uniforms in the lab. The number of lab techs is half of the number of uniforms. If there are 12 uniforms in the lab, and the lab techs share the coats and uniforms equally among them, how many coats and uniforms in total does each lab tech get?

answer:If there are 12 uniforms in the lab, then there are 6 times as many lab coats, so there are 12 x 6 = 72 lab coats. The number of lab techs is half the number of uniforms, so there are 12 / 2 = 6 lab techs. To share the coats and uniforms equally among the lab techs, each lab tech will get 72 coats / 6 techs = 12 coats. And each lab tech will also get 12 uniforms / 6 techs = 2 uniforms. Therefore, each lab tech will get a total of 12 coats + 2 uniforms = 14 items. 14 The answer is: 14

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